SuperStroker!
Pro
welterracer said:I just put in my water wetter.. If you read the label on the bottle it says that on a dyno test..
50/50 mix.. temp was 212degrees
just water... temp was 210 degrees
50/50 mix with waterwetter temp was 204
just water and waterwetter temp was 192
SO realistically runing this stuff in a sled could only make a 8 degree difference because you run a 50/50mix..
In ONLY a racing enviroment could you see a 20degree drop in temp.. where you would not run any antifreeze..
Welter, 8 degrees of heat loss under the same test conditions is INCREDIBLE! Do you realize how much thermal energy needs to be exchanged to drop coolant temps that much, under steady state conditions?
Try to look at this a different way. You don't start with a "heat soaked" cooling system, you end up with that when you seize your engine! In our case, turn the warning light on.
In a previous explaination, I talked about "the enviornment" and how it changes constantly.
The enviornment is the medium that allows heat to be transfered away from the exhangers, to snow, air or liquid. If the enviornment is the same temp as the coolant, no heat will exchange.
Luckily, this is not the case. So try to look at it this way.
If you provide a gross loss in coolant temp equal to 8 BTUs is quite substantial. What this means is the heat energy input from the engine, must be exponentially higher to ever reach steady state (because of the changing enviornment and non-steady state level of heat loss in BTUs)
to ever reach the piont where the warning light will turn on.
So it's energy input minus total heat loss over time. It is not constant.
Make any sense?
Smokeless1, thanks for the understanding and kind words, I was loosing my confidence.